The spin-only magnetic moment value of the co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The oxidation states of $Mn$ in $MnF_{4}$,$MnF_{3}$,and $MnF_{2}$ are $+4$,$+3$,and $+2$ respectively.The electronic configurations are:$MnF_{4} (

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) The oxidation states of $Mn$ in $MnF_{4}$,$MnF_{3}$,and $MnF_{2}$ are $+4$,$+3$,and $+2$ respectively.The electronic configurations are:$MnF_{4} (Mn^{4+}) = [Ar] 3d^{3}$$MnF_{3} (Mn^{3+}) = [Ar] 3d^{4}$$MnF_{2} (Mn^{2+}) = [Ar] 3d^{5}$Among these,$Mn^{3+}$ is the strongest oxidizing agent because it can easily gain an electron to form the stable $d^{5}$ configuration $(Mn^{2+})$.For $Mn^{3+}$ $(3d^{4})$,the number of unpaired electrons $(n)$ is $4$.The spin-only magnetic moment is given by $\mu = \sqrt{n(n+2)} \ B.M.$$\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.89 \ B.M.$The nearest integer value is $5$.

The spin-only magnetic moment value of the compound with the strongest oxidizing ability among $MnF_{4}$,$MnF_{3}$,and $MnF_{2}$ is $............$ $B.M.$ [nearest integer]

Similar Questions

Of the following outer electronic configurations of atoms,the highest oxidation state is achieved by which one of them?

In the electronic configuration of which of the following elements is an electron arranged in the $5d$ orbital?

Which of the following statements regarding transition elements is incorrect?

Transition elements show high melting points. Why?

Higher second ionisation enthalpies than expected are observed for

Vedclass Test Series

Exam Paper Generator

Online Exam Module