The spin-only magnetic moment value of an oct | vedclass

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Question

(A) First,identify the coordination compounds and their ionization behavior:$CoCl_{3} \cdot 4NH_{3} \rightarrow [Co(NH_{3})_{4}Cl_{2}]Cl$ (gives $1$ m

Vedclass · Accepted Answer

$3$

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(A) First,identify the coordination compounds and their ionization behavior:$CoCl_{3} \cdot 4NH_{3} \rightarrow [Co(NH_{3})_{4}Cl_{2}]Cl$ (gives $1$ mole of $AgCl$)$NiCl_{2} \cdot 6H_{2}O \rightarrow [Ni(H_{2}O)_{6}]Cl_{2}$ (gives $2$ moles of $AgCl$)$PtCl_{4} \cdot 2HCl \rightarrow H_{2}[PtCl_{6}]$ (gives $0$ moles of $AgCl$)The complex that gives $2$ moles of $AgCl$ is $[Ni(H_{2}O)_{6}]Cl_{2}$.In $[Ni(H_{2}O)_{6}]^{2+}$,the oxidation state of $Ni$ is $+2$,and its electronic configuration is $[Ar]3d^{8}$.For $Ni^{2+}$ $(d^{8})$,there are $2$ unpaired electrons $(n=2)$.The spin-only magnetic moment is calculated as $\mu = \sqrt{n(n+2)} \ B.M. = \sqrt{2(2+2)} \ B.M. = \sqrt{8} \ B.M. \approx 2.83 \ B.M.$The nearest integer value is $3$ $B.M.$

The spin-only magnetic moment value of an octahedral complex among $CoCl_{3} \cdot 4NH_{3}$,$NiCl_{2} \cdot 6H_{2}O$ and $PtCl_{4} \cdot 2HCl$,which upon reaction with excess of $AgNO_{3}$ gives $2$ moles of $AgCl$ is $....$ $B.M.$ (Nearest Integer)

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