The 'Spin only' magnetic moment for [Ni(NH_3) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $NH_3$ acts as a weak field ligand with $Ni^{2+}$.The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.For $Ni^{2+}$,the configuratio

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(B) $NH_3$ acts as a weak field ligand with $Ni^{2+}$.The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.For $Ni^{2+}$,the configuration is $3d^8$.The $3d$ orbitals are filled as follows: two orbitals are doubly occupied,and two orbitals are singly occupied (total $2$ unpaired electrons).The spin-only magnetic moment is calculated as:$\mu = \sqrt{n(n+2)} \ BM$Where $n = 2$ (number of unpaired electrons).$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.82 \ BM$.To express this as $x 	imes 10^{-1} \ BM$,we have $2.82 = 28.2 	imes 10^{-1}$.Rounding to the nearest integer,$x = 28$.

The 'Spin only' magnetic moment for $[Ni(NH_3)_6]^{2+}$ is $ . . . . . . \times 10^{-1} \ BM$.
(Given: Atomic number of $Ni = 28$)

Similar Questions

Which of the following represents a pair of enantiomers?

Indicate the number of unpaired electrons in $K_3[Fe(CN)_6]$ and $K_4[Fe(CN)_6]$.

Which of the following isomerism is not possible for complexes having molecular formulas:
$(i) \ Pt(SCN)_2 \cdot 3PEt_3$
$(ii) \ CoBr \cdot SO_4 \cdot 5NH_3$
$(iii) \ FeCl_3 \cdot 6H_2O$

$A$ complex compound which can show optical isomerism but not geometrical isomerism is:

The correct order of spin-only magnetic moment of the following complex ions is: (Given At. No. $Fe: 26, Co: 27$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The 'Spin only' magnetic moment for $[Ni(NH_3)_6]^{2+}$ is $ . . . . . . \times 10^{-1} \ BM$.(Given: Atomic number of $Ni = 28$)