The speed of a particle is doubled,its kineti | vedclass

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(C) The kinetic energy $(K)$ of a particle of mass $(m)$ moving with speed $(v)$ is given by the formula: $K = \frac{1}{2}mv^2$.If the speed is double

Vedclass · Accepted Answer

becomes four times

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(C) The kinetic energy $(K)$ of a particle of mass $(m)$ moving with speed $(v)$ is given by the formula: $K = \frac{1}{2}mv^2$.If the speed is doubled,the new speed becomes $v' = 2v$.The new kinetic energy $(K')$ will be: $K' = \frac{1}{2}m(v')^2 = \frac{1}{2}m(2v)^2$.$K' = \frac{1}{2}m(4v^2) = 4 	imes (\frac{1}{2}mv^2) = 4K$.Therefore,the kinetic energy becomes four times the original kinetic energy.

The speed of a particle is doubled,its kinetic energy:

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