Difficult
The specific rate constant of decomposition of a compound is given by $\ln k = 5.0 - \frac{12000}{T}$. The activation energy of decomposition for this compound at $300 \ K$ is
- A$24 \ kcal \ mol^{-1}$
- B$12 \ kcal \ mol^{-1}$
- C$24 \ cal \ mol^{-1}$
- D$12 \ cal \ mol^{-1}$
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