The specific conductance of a saturated solution of silver bromide is $\kappa \ S \ cm^{-1}$. The limiting ionic conductances for $Ag^{+}$ and $Br^{-}$ are $x$ and $y$ $S \ cm^2 \ mol^{-1}$ respectively. Then the solubility of silver bromide (in $g/L$) will be $(Ag = 108, Br = 80)$.

• A
  $\frac{\kappa \times 188}{x + y}$
• B
  $\frac{\kappa \times 1000}{x - y}$
• C
  $\frac{x + y \times 1000}{\kappa \times 188}$
• D
  $\frac{\kappa \times 188 \times 1000}{x + y}$