The species having bond angles of 120^{circ} | vedclass

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(C) To determine the species with a bond angle of $120^{\circ}$,we analyze the hybridization and geometry of each molecule:$1$. $ClF_3$: The central a

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$BCl_3$

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(C) To determine the species with a bond angle of $120^{\circ}$,we analyze the hybridization and geometry of each molecule:$1$. $ClF_3$: The central atom $Cl$ has $7$ valence electrons. It forms $3$ bonds with $F$ atoms and has $2$ lone pairs. The hybridization is $sp^3d$,and the geometry is $T$-shaped with bond angles less than $90^{\circ}$.$2$. $NCl_3$: The central atom $N$ has $5$ valence electrons. It forms $3$ bonds with $Cl$ atoms and has $1$ lone pair. The hybridization is $sp^3$,and the geometry is pyramidal with bond angles approximately $107^{\circ}$.$3$. $BCl_3$: The central atom $B$ has $3$ valence electrons. It forms $3$ bonds with $Cl$ atoms and has no lone pairs. The hybridization is $sp^2$,and the geometry is trigonal planar with bond angles of $120^{\circ}$.$4$. $PH_3$: The central atom $P$ has $5$ valence electrons. It forms $3$ bonds with $H$ atoms and has $1$ lone pair. The geometry is pyramidal with bond angles close to $93^{\circ}$.Therefore,$BCl_3$ is the correct species.

The species having bond angles of $120^{\circ}$ is

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