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(D) The absolute value of any real number is always non-negative,i.e.,$|x-1| \geq 0$ for all $x \in \mathbb{R}$.Given the inequality $|x-1| \leq -1$,w

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$\emptyset$

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(D) The absolute value of any real number is always non-negative,i.e.,$|x-1| \geq 0$ for all $x \in \mathbb{R}$.Given the inequality $|x-1| \leq -1$,we are looking for values of $x$ such that the absolute value is less than or equal to $-1$.Since a non-negative number can never be less than or equal to a negative number,there is no real value of $x$ that satisfies this condition.Therefore,the solution set is the empty set,denoted by $\emptyset$.

The solution set of $|x-1| \leq -1$ is...

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