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(A) The reaction of $NaCl$ with $AgNO_3$ produces a white precipitate of $AgCl$ $(Y)$: $NaCl + AgNO_3 	o AgCl(s) + NaNO_3$.$AgCl$ is soluble in $NH_4

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$NaCl$

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(A) The reaction of $NaCl$ with $AgNO_3$ produces a white precipitate of $AgCl$ $(Y)$: $NaCl + AgNO_3 	o AgCl(s) + NaNO_3$.$AgCl$ is soluble in $NH_4OH$ due to the formation of a soluble complex $Z$: $AgCl + 2NH_4OH 	o [Ag(NH_3)_2]Cl + 2H_2O$.When this complex $Z$ is treated with dilute $HNO_3$,the $NH_3$ is neutralized,and the white precipitate of $AgCl$ $(Y)$ reappears: $[Ag(NH_3)_2]Cl + 2HNO_3 	o AgCl(s) + 2NH_4NO_3$.$CH_3Cl$ is a covalent haloalkane and does not react with $AgNO_3$ to form a precipitate. $NaBr$ and $NaI$ form pale yellow and yellow precipitates,respectively.

The solution of a chemical compound $X$ reacts with $AgNO_3$ solution to form a white precipitate of $Y$,which dissolves in $NH_4OH$ to give a complex $Z$. When $Z$ is treated with dilute $HNO_3$,$Y$ reappears. The chemical compound $X$ can be:

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