The solubility of anhydrous AlCl_3 and hydrou | vedclass

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Question

(B) Anhydrous $AlCl_3$ is a strong Lewis acid and is electron-deficient.
It readily dissolves in diethyl ether because the lone pairs of electrons on

Vedclass · Accepted Answer

$S_1 > S_2$

Vedclass · Answer

(B) Anhydrous $AlCl_3$ is a strong Lewis acid and is electron-deficient.
It readily dissolves in diethyl ether because the lone pairs of electrons on the oxygen atom of diethyl ether are donated to the $Al$ atom of $AlCl_3$,forming a coordinate bond.
In contrast,hydrous $AlCl_3$ (usually $AlCl_3 \cdot 6H_2O$) contains water molecules already coordinated to the $Al^{3+}$ ion,which satisfies its electron deficiency and makes it a much weaker Lewis acid.
Therefore,the solubility of anhydrous $AlCl_3$ $(S_1)$ is significantly higher than that of hydrous $AlCl_3$ $(S_2)$.
Thus,$S_1 > S_2$.

Column-$I$	Column-$II$
$A$. Methanol	$p$. Conversion of phenol to salicylic acid
$B$. Kolbe's reaction	$q$. Wood spirit
$C$. Williamson's reaction	$r$. Vapours are passed over heated copper at $573 \ K$
$D$. Conversion of $2^\circ$ alcohol to ketone	$s$. Reaction of alkyl halide with sodium alkoxide

The solubility of anhydrous $AlCl_3$ and hydrous $AlCl_3$ in diethyl ether are $S_1$ and $S_2$ respectively. Then:

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