The solubility of a sparingly soluble salt A_ | vedclass

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(A) The solubility product $K_{sp}$ for a salt $A_x B_y$ is given by the formula: $K_{sp} = x^x \cdot y^y \cdot (S)^{x+y}$,where $S$ is the solubility

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$x = 1, y = 2$

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(A) The solubility product $K_{sp}$ for a salt $A_x B_y$ is given by the formula: $K_{sp} = x^x \cdot y^y \cdot (S)^{x+y}$,where $S$ is the solubility.Given $S = 1.4 	imes 10^{-4} \ M$ and $K_{sp} = 1.1 	imes 10^{-11}$.Substituting the values: $1.1 	imes 10^{-11} = x^x \cdot y^y \cdot (1.4 	imes 10^{-4})^{x+y}$.If we assume $x+y = 3$,then $(1.4 	imes 10^{-4})^3 = 2.744 	imes 10^{-12}$.Then $x^x \cdot y^y = \frac{1.1 	imes 10^{-11}}{2.744 	imes 10^{-12}} \approx 4$.For $x=1, y=2$,$x^x \cdot y^y = 1^1 \cdot 2^2 = 4$.Thus,the values are $x=1, y=2$.

The solubility of a sparingly soluble salt $A_x B_y$ in water at $25\,^{\circ}C$ is $1.4 \times 10^{-4} \ M$. The solubility product is $1.1 \times 10^{-11}$. The values of $x$ and $y$ may be

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