The solubility of a salt A_2B_3 is 10^{-3} M | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a salt of the type $A_2B_3$,the dissociation is given by: $A_2B_3(s) \rightleftharpoons 2A^{3+}(aq) + 3B^{2-}(aq)$.If $S$ is the solubility,th

Vedclass · Accepted Answer

$1.08 	imes 10^{-13}$

Vedclass · Answer

(A) For a salt of the type $A_2B_3$,the dissociation is given by: $A_2B_3(s) ightleftharpoons 2A^{3+}(aq) + 3B^{2-}(aq)$.If $S$ is the solubility,then $[A^{3+}] = 2S$ and $[B^{2-}] = 3S$.The solubility product $K_{sp}$ is given by: $K_{sp} = [A^{3+}]^2 [B^{2-}]^3$.$K_{sp} = (2S)^2 	imes (3S)^3 = 4S^2 	imes 27S^3 = 108S^5$.Given $S = 10^{-3} \ M$,substituting the value:$K_{sp} = 108 	imes (10^{-3})^5 = 108 	imes 10^{-15} = 1.08 	imes 10^{-13}$.

The solubility of a salt $A_2B_3$ is $10^{-3} \ M$. What will be its solubility product?

Similar Questions

For the precipitation reaction of $Ag^{\oplus}$ ions with $NaCl,$ which of the following statements is true?

The value of $K_{sp}$ for $B_2CO_3$ is $3.2 \times 10^{-5}$. The concentration of $B^{+}$ in its saturated solution is :-

Which of the following substances is insoluble in dilute hydrochloric acid?

The solubility of a salt of weak acid $(AB)$ at $pH = 3$ is $Y \times 10^{-3} \ mol \ L^{-1}$. The value of $Y$ is (Given that the value of solubility product of $AB$ $(K_{sp}) = 2 \times 10^{-10}$ and the value of ionization constant of $HB$ $(K_{a}) = 1 \times 10^{-8}$)

The solubility of $AgCl$ in water is $1.43 \times 10^{-3} \ g \ L^{-1}$. What is the value of $K_{sp}$ for $AgCl$ at $25 \ ^oC$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module