The solubility of $PbI_2$ at $25\,^{\circ}C$ is $0.7\, g\, L^{-1}$. The solubility product of $PbI_2$ at this temperature is (molar mass of $PbI_2 = 461.2\, g\, mol^{-1}$)

  • A
    $1.40 \times 10^{-9}$
  • B
    $0.14 \times 10^{-9}$
  • C
    $140 \times 10^{-9}$
  • D
    $14.0 \times 10^{-9}$

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