The slope of a curve at any point is the reciprocal of twice the ordinate at the point and it passes through the point $(4, 3)$. The equation of the curve is
- A$x^2 = y + 5$
- B$y^2 = x - 5$
- C$y^2 = x + 5$
- D$x^2 = y - 5$
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Similar Questions
The solution of ${e^{2x - 3y}}dx + {e^{2y - 3x}}dy = 0$ is
Medium
View SolutionFind a particular solution satisfying the given condition:
$x(x^{2}-1) \frac{dy}{dx}=1; y=0$ when $x=2$
$x(x^{2}-1) \frac{dy}{dx}=1; y=0$ when $x=2$
Difficult
View SolutionIf $y(x)$ is the solution of the differential equation $(x+2) \frac{dy}{dx} = x^2+4x-9, x \neq -2$ and $y(0) = 0$,then $y(-4)$ is equal to
The equation of the curve passing through $\left(\frac{\pi}{6}, 0\right)$ and satisfying the differential equation $(e^y+1) \cos x \, dx + e^y \sin x \, dy = 0$ is:
If $2x - y + c \log(x - 2y - 4) = k$ is the general solution of $\frac{dy}{dx} = \frac{2x - 4y - 5}{x - 2y + 2}$,then $c =$
DifficultAP EAMCET 2022
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