The simple interest accrued on an amount of R | vedclass

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(B) Given: Principal $(P) = Rs. 19800$,Simple Interest $(SI) = Rs. 7128$,Time $(T) = 3$ years.First,calculate the rate of interest $(R)$ using the for

Vedclass · Accepted Answer

$8017.5744$

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(B) Given: Principal $(P) = Rs. 19800$,Simple Interest $(SI) = Rs. 7128$,Time $(T) = 3$ years.First,calculate the rate of interest $(R)$ using the formula: $SI = \frac{P 	imes R 	imes T}{100}$.$7128 = \frac{19800 	imes R 	imes 3}{100} \Rightarrow 7128 = 198 	imes R 	imes 3$.$7128 = 594 	imes R \Rightarrow R = \frac{7128}{594} = 12 \%$.Now,calculate the compound interest $(CI)$ using the formula: $CI = P \left[ (1 + \frac{R}{100})^T - 1 ight]$.$CI = 19800 \left[ (1 + \frac{12}{100})^3 - 1 ight] = 19800 \left[ (1.12)^3 - 1 ight]$.$(1.12)^3 = 1.404928$.$CI = 19800 	imes (1.404928 - 1) = 19800 	imes 0.404928$.$CI = Rs. 8017.5744$.

The simple interest accrued on an amount of $Rs. 19800$ at the end of $3$ years is $Rs. 7128$. What would be the compound interest (in $Rs.$) accrued on the same amount at the same rate in the same period?

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