(B) The reaction of a silver salt of a carboxylic acid with an alkyl halide $(R-X)$ is known as the alkylation of carboxylate ions. This reaction proc

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(B) The reaction of a silver salt of a carboxylic acid with an alkyl halide $(R-X)$ is known as the alkylation of carboxylate ions. This reaction proceeds via a nucleophilic substitution mechanism $(S_N2)$ where the carboxylate ion $(R'COO^-)$ acts as a nucleophile and attacks the alkyl halide. The general reaction is: $R'COOAg + R-X \rightarrow R'COOR + AgX \downarrow$. The product formed is an ester.

Class 12 Chemistry 8-2.Carboxylic acids and Their derivative Properties of Carboxylic Acids and Their Derivatives

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The silver salt of a carboxylic acid on reaction with $R-X$ gives:

MHT CET 2009 All MHT CET

A
alkyl halide
B
ester
C
aldehyde
D
alcohol

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8-2.Carboxylic acids and Their derivative

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Properties of Carboxylic Acids and Their Derivatives

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The correct order of increasing acid strength of the compounds is:
$(A) CH_3CO_2H$
$(B) MeOCH_2CO_2H$
$(C) CF_3CO_2H$
$(D) (CH_3)_2CHCO_2H$

MediumAIEEE 2006

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Identify the compound $(B)$ in the following reaction sequence:
$2\text{-formylmethylbenzoic acid}$ $\xrightarrow{NaBH_4} (A)$ $\xrightarrow{H^{\oplus}, \Delta} (B) \text{ (Cyclic)}$

Medium

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The major product of the following reaction is:

DifficultJEE MAIN 2019

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In the reaction,$C_6H_5CHO + (CH_3CO)_2O \xrightarrow{CH_3COONa} (A)$,product $(A)$ is

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In the reaction $HCOOH \xrightarrow{H_2SO_4} CO + H_2O$,$H_2SO_4$ acts as:

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The silver salt of a carboxylic acid on reaction with $R-X$ gives:

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The correct order of increasing acid strength of the compounds is: $(A) CH_3CO_2H$ $(B) MeOCH_2CO_2H$ $(C) CF_3CO_2H$ $(D) (CH_3)_2CHCO_2H$

Identify the compound $(B)$ in the following reaction sequence:$2\text{-formylmethylbenzoic acid}$ $\xrightarrow{NaBH_4} (A)$ $\xrightarrow{H^{\oplus}, \Delta} (B) \text{ (Cyclic)}$

The major product of the following reaction is:

In the reaction,$C_6H_5CHO + (CH_3CO)_2O \xrightarrow{CH_3COONa} (A)$,product $(A)$ is

In the reaction $HCOOH \xrightarrow{H_2SO_4} CO + H_2O$,$H_2SO_4$ acts as:

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The correct order of increasing acid strength of the compounds is:
$(A) CH_3CO_2H$
$(B) MeOCH_2CO_2H$
$(C) CF_3CO_2H$
$(D) (CH_3)_2CHCO_2H$

Identify the compound $(B)$ in the following reaction sequence:
$2\text{-formylmethylbenzoic acid}$ $\xrightarrow{NaBH_4} (A)$ $\xrightarrow{H^{\oplus}, \Delta} (B) \text{ (Cyclic)}$