The sides of a triangle measure 12 , cm,16 , | vedclass

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(B) First,observe that the side lengths $12 \, cm$,$16 \, cm$,and $20 \, cm$ form a Pythagorean triple because $12^2 + 16^2 = 144 + 256 = 400 = 20^2$.

Vedclass · Accepted Answer

$96$

Vedclass · Answer

(B) First,observe that the side lengths $12 \, cm$,$16 \, cm$,and $20 \, cm$ form a Pythagorean triple because $12^2 + 16^2 = 144 + 256 = 400 = 20^2$. Since the square of the longest side equals the sum of the squares of the other two sides,this is a right-angled triangle. The area of a right-angled triangle is given by the formula: $	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$. Taking the base as $12 \, cm$ and the height as $16 \, cm$,we get: $	ext{Area} = \frac{1}{2} 	imes 12 	imes 16 = 6 	imes 16 = 96 \, cm^2$.

The sides of a triangle measure $12 \, cm$,$16 \, cm$,and $20 \, cm$. What is the area of the triangle in $cm^2$?

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