The sides of a triangle are a , cm,b , cm,and | vedclass

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Question

(B) We are given the semi-perimeter $s = \frac{a + b + c}{2}$.We have the equations:$s - a = 10 \implies a = s - 10$$s - b = 15 \implies b = s - 15$$s

Vedclass · Accepted Answer

$37$

Vedclass · Answer

(B) We are given the semi-perimeter $s = \frac{a + b + c}{2}$.We have the equations:$s - a = 10 \implies a = s - 10$$s - b = 15 \implies b = s - 15$$s - c = 12 \implies c = s - 12$Adding these three equations:$(s - a) + (s - b) + (s - c) = 10 + 15 + 12$$3s - (a + b + c) = 37$Since $a + b + c = 2s$,we substitute this into the equation:$3s - 2s = 37$$s = 37$Thus,the semi-perimeter $s$ is $37 \, cm$.

The sides of a triangle are $a \, cm$,$b \, cm$,and $c \, cm$. Also,its semi-perimeter is $s \, cm$. If $s - a = 10 \, cm$,$s - b = 15 \, cm$,and $s - c = 12 \, cm$,then $s = \dots \, cm$.

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