The shapes of XeF_4,XeF_5^- and SnCl_2 are | vedclass

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(C) For $XeF_4$: The central atom $Xe$ has $8$ valence electrons. It forms $4$ bonds with $F$ atoms and has $2$ lone pairs. The steric number is $6$ (

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square planar,pentagonal planar and angular

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(C) For $XeF_4$: The central atom $Xe$ has $8$ valence electrons. It forms $4$ bonds with $F$ atoms and has $2$ lone pairs. The steric number is $6$ ($sp^3d^2$ hybridization),resulting in a square planar geometry.For $XeF_5^-$: The central atom $Xe$ has $8$ valence electrons,plus $1$ from the negative charge,forming $5$ bonds with $F$ atoms and having $2$ lone pairs. The steric number is $7$ ($sp^3d^3$ hybridization),resulting in a pentagonal planar geometry.For $SnCl_2$: The central atom $Sn$ has $4$ valence electrons. It forms $2$ bonds with $Cl$ atoms and has $1$ lone pair. The steric number is $3$ ($sp^2$ hybridization),resulting in an angular or bent shape.

List-$A$	List-$B$
$(1)$ $AB_3E_2$	$(A)$ $BrF_5$
$(2)$ $AB_2E_2$	$(B)$ $NH_3$
$(3)$ $AB_5E$	$(C)$ $H_2O$
$(4)$ $AB_3E$	$(D)$ $ClF_3$

The shapes of $XeF_4$,$XeF_5^-$ and $SnCl_2$ are

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Match the following List-$A$ and List-$B$ correctly.

List-$A$ List-$B$

$(1)$ $AB_3E_2$ $(A)$ $BrF_5$

$(2)$ $AB_2E_2$ $(B)$ $NH_3$

$(3)$ $AB_5E$ $(C)$ $H_2O$

$(4)$ $AB_3E$ $(D)$ $ClF_3$

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