The shadow of a tower standing on a level gro | vedclass

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(D) Let the height of the tower be $h$ and the length of the shadow when the sun's altitude is $45^\circ$ be $x$.In $	riangle PMB$,$	an 45^\circ = \

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$30(\sqrt{3} + 1) \, m$

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(D) Let the height of the tower be $h$ and the length of the shadow when the sun's altitude is $45^\circ$ be $x$.In $	riangle PMB$,$	an 45^\circ = \frac{h}{x}$ $\Rightarrow 1 = \frac{h}{x}$ $\Rightarrow x = h$.In $	riangle PMA$,$	an 30^\circ = \frac{h}{x + 60} \Rightarrow \frac{1}{\sqrt{3}} = \frac{h}{h + 60}$.$h + 60 = h\sqrt{3} \Rightarrow h(\sqrt{3} - 1) = 60$.$h = \frac{60}{\sqrt{3} - 1} = \frac{60(\sqrt{3} + 1)}{3 - 1} = \frac{60(\sqrt{3} + 1)}{2} = 30(\sqrt{3} + 1) \, m$.

The shadow of a tower standing on a level ground is found to be $60 \, m$ longer when the sun's altitude is $30^\circ$ than when it is $45^\circ$. The height of the tower is

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