The self-inductance of a coil is L. Keeping t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The self-inductance $L$ of a solenoid is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $N$ is the number of turns,$A$ is the cross-sectio

Vedclass · Accepted Answer

$16L$

Vedclass · Answer

(D) The self-inductance $L$ of a solenoid is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $N$ is the number of turns,$A$ is the cross-sectional area,and $l$ is the length of the coil.From this formula,it is clear that $L \propto N^2$,provided that the length $l$ and area $A$ remain constant.Given that the number of turns is increased to four times,i.e.,$N' = 4N$.Therefore,the new self-inductance $L'$ will be $L' \propto (N')^2 = (4N)^2 = 16N^2$.Thus,$L' = 16L$.

The self-inductance of a coil is $L$. Keeping the length and area the same,the number of turns in the coil is increased to four times. The self-inductance of the coil will now be

Similar Questions

The equivalent quantity of mass in electricity is . . . . . . .

The dimensional formula of self-inductance is . . . . . . .

The unit of self-inductance of a coil is

$A$ $10\, V$ battery connected to $5\,\Omega$ resistance coil having inductance $10\, H$ through a switch drives a constant current in the circuit. The switch is suddenly opened and the time taken to open it is $2\, ms$. The average $emf$ induced across the coil is

To manufacture a solenoid of length $1 \,m$ and inductance $1 \,mH$, the length of thin wire required is (cross-sectional diameter of a solenoid is considerably less than the length).

Vedclass Test Series

Exam Paper Generator

Online Exam Module