The self-inductance of a circuit is numerical | vedclass

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(B) The energy stored in an inductor of self-inductance $L$ carrying a current $I$ is given by $U = \frac{1}{2} L I^2$.If we consider the work done to

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twice the work done in establishing the magnetic flux associated with unit current in the circuit.

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(B) The energy stored in an inductor of self-inductance $L$ carrying a current $I$ is given by $U = \frac{1}{2} L I^2$.If we consider the work done to establish the magnetic flux,it is equivalent to the energy stored in the magnetic field.For a unit current $(I = 1 \ A)$,the energy stored is $U = \frac{1}{2} L (1)^2 = \frac{L}{2}$.Therefore,$L = 2U$.This means the self-inductance $L$ is numerically equal to twice the work done (or energy stored) in establishing the magnetic flux associated with a unit current in the circuit.

The self-inductance of a circuit is numerically equal to

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