The roots of x^{2}+12x+36=0 are ........... | vedclass

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(D) The given quadratic equation is $x^{2} + 12x + 36 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = 1$,$b = 12$,and $c

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(D) The given quadratic equation is $x^{2} + 12x + 36 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = 1$,$b = 12$,and $c = 36$.The discriminant $D$ is calculated as $D = b^{2} - 4ac$.$D = (12)^{2} - 4(1)(36) = 144 - 144 = 0$.Since the discriminant $D = 0$,the roots of the quadratic equation are real and equal.Alternatively,the equation can be written as $(x + 6)^{2} = 0$,which gives $x = -6, -6$.

The roots of $x^{2}+12x+36=0$ are ...........

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