The rms speed of a gas molecule is V at press | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The root mean square (rms) speed of a gas molecule is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constan

Vedclass · Accepted Answer

$V$

Vedclass · Answer

(A) The root mean square (rms) speed of a gas molecule is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.Since the rms speed depends only on the temperature $T$ and the molar mass $M$ of the gas,it is independent of the pressure $P$ of the gas.Given that the temperature remains constant,the rms speed will remain unchanged even if the pressure is increased.Therefore,the new rms speed will be $V$.

The rms speed of a gas molecule is $V$ at pressure $P$. If the pressure is increased by two times,then the rms speed of the gas molecule at the same temperature will be

Similar Questions

The temperature at which the rms speed of oxygen molecules is $75 \%$ of the rms speed of nitrogen molecules at a temperature of $287^{\circ} C$ is: (in $^{\circ} C$)

The molecular masses of helium and oxygen are $4$ and $32$ respectively. The ratio of r.m.s speed of helium at $327^{\circ} C$ to r.m.s speed of oxygen at $27^{\circ} C$ will be

At a temperature of $27 \, ^\circ C$,the $rms$ speed of a gas is $1930 \, m/s$. The gas is:

If the absolute temperature of a gas is increased $5$ times,the r.m.s. velocity of the gas molecules will be

At what temperature $(^oC)$ will the $rms$ speed of hydrogen be double its value at $S.T.P.$? The pressure remains constant.

Vedclass Test Series

Exam Paper Generator

Online Exam Module