The resultant magnetic moment of a neon atom will be

State the direction of the magnetic dipole moment (from $S$ to $N$ pole of the magnet) and write the unit of the magnetic dipole moment.

Two like magnetic poles of strength $10$ and $40$ $SI$ units are separated by a distance of $30 \, cm$. The intensity of the magnetic field is zero on the line joining them at:

Two similar bar magnets $P$ and $Q$,each of magnetic moment $M$,are taken. If $P$ is cut along its axial line and $Q$ is cut along its equatorial line,all the four pieces obtained have:

The magnetic moment of a magnet of length $10\, cm$ and pole strength $4.0\, Am$ will be......$A\,m^2$.

The average dipole moment of $Fe$ atoms is $1.8 \times 10^{-23} \ A-m^2$. The magnetic moment of an iron rod of length $10 \ cm$ and diameter $1 \ cm$ is........$A-m^2$: (density and atomic weight of $Fe$ are $7.87 \ g/cm^3$ and $55.87$ respectively).