The resonance frequency of an $L-C-R$ $AC$ circuit is $\nu_{0}$. If the capacitance is made $4$ times its initial value,then the new resonance frequency will become . . . . . . .

At resonance,the value of current in a series $L-C-R$ circuit is: (Symbols have their usual meanings.)

In a non-resonant $LCR$ series circuit,what will be the nature of the circuit for frequencies higher than the resonance frequency?

In an $LCR$ circuit having $L = 8.0 \, H$,$C = 0.5 \, \mu F$,and $R = 100 \, \Omega$ in series,the resonance frequency in radians per second is:

$A$ series $L-C-R$ circuit containing a resistance of $120 \Omega$ has an angular frequency of $4 \times 10^5 \ rad \ s^{-1}$. At resonance,the voltage across the resistance and the inductor are $60 \ V$ and $40 \ V$ respectively. The value of the inductance is: (in $mH$)

In a series $LR$ circuit with $X_L = R$, the power factor is $P_1$. If a capacitor of capacitance $C$ with $X_C = X_L$ is added to the circuit, the power factor becomes $P_2$. The ratio of $P_1$ to $P_2$ will be: