The resistances in the following circuit are $R_1 = R_2 = R_3 = 6.0 \ \Omega$. The emf of the battery is $12 \ V$. When switch $S$ is closed,the potential across resistance $R_1$ changes by an amount:

  • A
    $-2 \ V$
  • B
    $+2 \ V$
  • C
    $-4 \ V$
  • D
    $+4 \ V$

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