The resistance of the series combination of t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the resistance of each identical resistor be $R$.When connected in series,the equivalent resistance is $S = R + R = 2R$.When connected in para

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) Let the resistance of each identical resistor be $R$.When connected in series,the equivalent resistance is $S = R + R = 2R$.When connected in parallel,the equivalent resistance is $P = \frac{R 	imes R}{R + R} = \frac{R^2}{2R} = \frac{R}{2}$.Given the relation $S = nP$,we substitute the expressions for $S$ and $P$:$2R = n \left( \frac{R}{2} ight)$.Dividing both sides by $R$ (assuming $R 
eq 0$):$2 = \frac{n}{2}$.Multiplying by $2$,we get $n = 4$.Thus,the value of $n$ is $4$.

The resistance of the series combination of two identical resistors is $S$. When they are joined in parallel,the total resistance is $P$. If $S = nP$,then the minimum possible value of $n$ is

Similar Questions

The equivalent resistance between ends $A$ and $B$ is

$6 \Omega$ and $12 \Omega$ resistors are connected in parallel. This combination is connected in series with a $10 \text{ V}$ battery and a $6 \Omega$ resistor. What is the potential difference between the terminals of the $12 \Omega$ resistor (in $\text{ V}$)?

The resistance of the series combination of two resistances is $S$. When they are joined in parallel,the total resistance is $P$. If $S = nP$,then the minimum possible value of $n$ is

Two bulbs,one of $200 \ V, 60 \ W$ and the other of $200 \ V, 100 \ W$,are connected in series to a $200 \ V$ supply. The power consumed will be ................ $W$.

In the given network,the equivalent resistance between $A$ and $B$ is .............. $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module