The resistance of the platinum wire of a plat | vedclass

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Question

(D) Given:
Resistance at ice point $(R_0) = 5\; \Omega$
Resistance at steam point $(R_{100}) = 5.39\; \Omega$
Resistance in hot bath $(R_t) = 5.795

Vedclass · Accepted Answer

$203.85$

Vedclass · Answer

(D) Given:
Resistance at ice point $(R_0) = 5\; \Omega$
Resistance at steam point $(R_{100}) = 5.39\; \Omega$
Resistance in hot bath $(R_t) = 5.795\; \Omega$
The formula for temperature $(t)$ in a platinum resistance thermometer is given by:
$t = \frac{R_t - R_0}{R_{100} - R_0} 	imes 100$
Substituting the values:
$t = \frac{5.795 - 5}{5.39 - 5} 	imes 100$
$t = \frac{0.795}{0.39} 	imes 100$
$t = 2.03846 	imes 100$
$t \approx 203.85^{\circ}C$

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