The resistance of a galvanometer is $50\, \Omega$ and the maximum current which can be passed through it is $0.002\, A$. What resistance must be connected to it in order to convert it into an ammeter of range $0 - 0.5\, A$?

In an ammeter, $0.2\%$ of the main current passes through the galvanometer. If the resistance of the galvanometer is $G$, the resistance of the ammeter will be

$A$ moving coil galvanometer allows a full-scale current of $10^{-4} \ A$. $A$ series resistance of $2 \ M\Omega$ is required to convert the above galvanometer into a voltmeter of range $0-5 \ V$. Therefore,the value of shunt resistance required to convert the above galvanometer into an ammeter of range $0-10 \ mA$ is .... $\Omega$.

This question has Statement-$I$ and Statement-$II$. Of the four choices given after the statements,choose the one that best describes the two statements.
Statement-$I$: Higher the range,greater is the resistance of an ammeter.
Statement-$II$: To increase the range of an ammeter,an additional shunt needs to be used across it.

Voltmeters $V_1$ and $V_2$ are connected in series across a $D.C.$ line. $V_1$ reads $80 \, V$ and has a resistance per volt of $200 \, \Omega/V$. $V_2$ has a total resistance of $32 \, k\Omega$. The line voltage is ............. (in $V$)

Derive the expression for the shunt resistance required to increase the current-measuring capacity of a galvanometer by a factor of $n$.