The resistance of a galvanometer coil is $R$. What is the shunt resistance required to convert it into an ammeter of range $4$ times?

The deflection in a moving coil galvanometer of resistance $45 \Omega$ falls from $30$ divisions to $3$ divisions. The length of the shunt wire required to convert the galvanometer into an ammeter is [specific resistance of the material of the shunt wire $= 5 \times 10^{-7} \Omega m$ and area of cross-section of the wire $= 4 \times 10^{-7} m^2$]. (in $m$)

An ammeter, suspected to give inaccurate reading, is connected in series with a silver voltameter. The ammeter indicates $0.54\, A$. A steady current passed for one hour deposits $2.0124\, g$ of silver. If the $E.C.E.$ of silver is $1.118 \times 10^{-3}\, g\, C^{-1}$, then the error in ammeter reading is ................ $A$.

$A$ galvanometer of $10 \,\Omega$ resistance gives full scale deflection with $0.01 \, A$ of current. It is to be converted into an ammeter for measuring $10 \, A$ current. The value of shunt resistance required will be

Write the equation for the maximum torque acting on a current-carrying loop in a galvanometer.

$A$ galvanometer having coil resistance $10 \ \Omega$ shows a full scale deflection for a current of $3 \ mA$. For it to measure a current of $8 \ A$,the value of the shunt should be: