The resistance of a conductivity cell containing $0.001 \ M \ KCl$ solution at $298 \ K$ is $1500 \ \Omega$. What is the cell constant if the conductivity of $0.001 \ M \ KCl$ solution at $298 \ K$ is $0.146 \times 10^{-3} \ S \ cm^{-1}$?
(N/A) Given:
Conductivity,$\kappa = 0.146 \times 10^{-3} \ S \ cm^{-1}$
Resistance,$R = 1500 \ \Omega$
The formula for cell constant $(G^*)$ is:
$G^* = \kappa \times R$
Substituting the values:
$G^* = (0.146 \times 10^{-3} \ S \ cm^{-1}) \times (1500 \ \Omega)$
$G^* = 0.219 \ cm^{-1}$
Thus,the cell constant is $0.219 \ cm^{-1}$.
Conductivity,$\kappa = 0.146 \times 10^{-3} \ S \ cm^{-1}$
Resistance,$R = 1500 \ \Omega$
The formula for cell constant $(G^*)$ is:
$G^* = \kappa \times R$
Substituting the values:
$G^* = (0.146 \times 10^{-3} \ S \ cm^{-1}) \times (1500 \ \Omega)$
$G^* = 0.219 \ cm^{-1}$
Thus,the cell constant is $0.219 \ cm^{-1}$.
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