The resistance of a coil for dc is R ohms. In | vedclass

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(B) coil possesses both resistance $R$ and inductance $L$. For $dc$, the frequency $f = 0$, so the inductive reactance $X_L = 2\pi fL = 0$. Thus, the

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Will increase

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(B) coil possesses both resistance $R$ and inductance $L$. For $dc$, the frequency $f = 0$, so the inductive reactance $X_L = 2\pi fL = 0$. Thus, the effective resistance is simply $R$. For $ac$, the frequency $f > 0$, so the inductive reactance $X_L = 2\pi fL$ is non-zero. The effective resistance (impedance) of the coil in an $ac$ circuit is given by $Z = \sqrt{R^2 + X_L^2}$. Since $X_L^2 > 0$, it follows that $Z > R$. Therefore, the effective resistance of the coil increases in an $ac$ circuit.

The resistance of a coil for $dc$ is $R$ ohms. In $ac$, the effective resistance of the coil:

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