The relative reactivities for the replacement | vedclass

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(C) The reactant is $3$-methylpentane. Let us identify the number of hydrogen atoms of each type:$1^o$ hydrogens: There are $9$ such hydrogens ($3$ at

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$16/31$

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(C) The reactant is $3$-methylpentane. Let us identify the number of hydrogen atoms of each type:$1^o$ hydrogens: There are $9$ such hydrogens ($3$ at each terminal methyl group).$2^o$ hydrogens: There are $4$ such hydrogens ($2$ at $C_2$ and $2$ at $C_4$).$3^o$ hydrogens: There is $1$ such hydrogen (at $C_3$).The relative rates of formation are calculated as (Number of $H$ atoms) $	imes$ (Relative reactivity):For $1^o$ products: $9 	imes 1 = 9$For $2^o$ products: $4 	imes 4 = 16$For $3^o$ products: $1 	imes 6 = 6$Total relative rate = $9 + 16 + 6 = 31$.The product shown is a $2^o$ chloro derivative formed by replacing a hydrogen at $C_2$ or $C_4$. The relative amount of this specific product is $16/31$.

The relative reactivities for the replacement of $-H$ are $3^o : 2^o : 1^o = 6 : 4 : 1$. For the reaction shown in the image,determine the relative amount of the given product.

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