The relation between voltage sensitivity ({si | vedclass

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Question

(A) Current sensitivity $({\sigma _i})$ is defined as the deflection per unit current: ${\sigma _i} = \frac{	heta}{I}$.Voltage sensitivity $({\sigma

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$\frac{{\sigma _i}}{G} = {\sigma _V}$

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(A) Current sensitivity $({\sigma _i})$ is defined as the deflection per unit current: ${\sigma _i} = \frac{	heta}{I}$.Voltage sensitivity $({\sigma _V})$ is defined as the deflection per unit voltage: ${\sigma _V} = \frac{	heta}{V}$.Since $V = I \cdot G$,where $G$ is the resistance of the galvanometer,we can substitute $V$ in the voltage sensitivity equation:${\sigma _V} = \frac{	heta}{I \cdot G}$.Substituting ${\sigma _i} = \frac{	heta}{I}$ into the expression for ${\sigma _V}$,we get:${\sigma _V} = \frac{{\sigma _i}}{G}$.Therefore,the relation is $\frac{{\sigma _i}}{G} = {\sigma _V}$.

The relation between voltage sensitivity $({\sigma _V})$ and current sensitivity $({\sigma _i})$ of a moving coil galvanometer is (Resistance of Galvanometer = $G$)

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