The refractive index of flint glass for blue | vedclass

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Question

(A) The dispersive power $\omega$ of a material is defined as the ratio of the angular dispersion between the extreme colors to the mean deviation.Mat

Vedclass · Accepted Answer

$0.0276$

Vedclass · Answer

(A) The dispersive power $\omega$ of a material is defined as the ratio of the angular dispersion between the extreme colors to the mean deviation.Mathematically,it is given by the formula: $\omega = \frac{\mu_F - \mu_C}{\mu_D - 1}$Given:Refractive index for blue $F$ line,$\mu_F = 1.6333$Refractive index for red $C$ line,$\mu_C = 1.6161$Refractive index for yellow $D$ line,$\mu_D = 1.622$Substituting the values into the formula:$\omega = \frac{1.6333 - 1.6161}{1.622 - 1}$$\omega = \frac{0.0172}{0.622}$$\omega = 0.02765... \approx 0.0276$Thus,the correct option is $A$.

The refractive index of flint glass for blue $F$ line is $1.6333$ and red $C$ line is $1.6161.$ If the refractive index for yellow $D$ line is $1.622,$ the dispersive power of the glass is

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