The refracting angle of a glass prism is 30^{ | vedclass

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(D) Given: Refracting angle $A = 30^{\circ}$,Refractive index $\mu = 1.5$,and angle of incidence $i_1 = 0^{\circ}$ (since the ray is perpendicular to

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$18.6$

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(D) Given: Refracting angle $A = 30^{\circ}$,Refractive index $\mu = 1.5$,and angle of incidence $i_1 = 0^{\circ}$ (since the ray is perpendicular to the face).Since $i_1 = 0^{\circ}$,the angle of refraction $r_1$ is also $0^{\circ}$.Using the relation $r_1 + r_2 = A$,we get $0^{\circ} + r_2 = 30^{\circ}$,so $r_2 = 30^{\circ}$.Applying Snell's Law at the second face: $\mu \sin(r_2) = 1 \cdot \sin(i_2)$.$1.5 \cdot \sin(30^{\circ}) = \sin(i_2)$.$1.5 \cdot 0.5 = \sin(i_2) \Rightarrow \sin(i_2) = 0.75$.Given $\sin(48.6^{\circ}) = 0.75$,therefore $i_2 = 48.6^{\circ}$.The angle of deviation $\delta$ is given by $\delta = (i_1 + i_2) - A$.$\delta = (0^{\circ} + 48.6^{\circ}) - 30^{\circ} = 18.6^{\circ}$.

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