Class 11PhysicsMechanical Properties of SolidsBasic of Elasticity, Stress and Strain relationship and Graphical analysis
EasyThe reason for the change in shape of a regular body is
- AVolume stress
- BShearing strain
- CLongitudinal strain
- DMetallic strain
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Similar Questions
Match the physical quantities in Column-$I$ with the details given in Column-$II$ appropriately:
Column-$I$ Column-$II$ $(a)$ $\text{Stress} \propto \text{Strain}$ $(i)$ $M^1 L^{-1} T^{-2}$ $(b)$ $\text{Dimensional formula for compressibility}$ $(ii)$ $M^{-1} L^1 T^2$ $(iii)$ $\text{Poisson's ratio}$ $(iv)$ $\text{Hooke's law}$
| Column-$I$ | Column-$II$ |
|---|---|
| $(a)$ $\text{Stress} \propto \text{Strain}$ | $(i)$ $M^1 L^{-1} T^{-2}$ |
| $(b)$ $\text{Dimensional formula for compressibility}$ | $(ii)$ $M^{-1} L^1 T^2$ |
| $(iii)$ $\text{Poisson's ratio}$ | |
| $(iv)$ $\text{Hooke's law}$ |
Easy
View Solution$A$ cable that can support a load $W$ is cut into two equal parts. The maximum load that can be supported by either part is
Medium
View SolutionMatch List-$I$ with List-$II$ :
List-$I$ List-$II$ $(A)$ $A$ force that restores an elastic body of unit area to its original state $(I)$ Bulk modulus $(B)$ Two equal and opposite forces parallel to opposite faces $(II)$ Young's modulus $(C)$ Forces perpendicular everywhere to the surface per unit area same everywhere $(III)$ Stress $(D)$ Two equal and opposite force perpendicular to opposite faces $(IV)$ Shear modulus
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ $A$ force that restores an elastic body of unit area to its original state | $(I)$ Bulk modulus |
| $(B)$ Two equal and opposite forces parallel to opposite faces | $(II)$ Young's modulus |
| $(C)$ Forces perpendicular everywhere to the surface per unit area same everywhere | $(III)$ Stress |
| $(D)$ Two equal and opposite force perpendicular to opposite faces | $(IV)$ Shear modulus |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2024
View SolutionStress to strain ratio is equivalent to
Easy
View SolutionThe ratio of radii of two wires of same material is $2: 1$. If these wires are stretched by equal force,the ratio of stresses produced in them is .............
Easy
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