The reagent that can distinguish between silver and lead salt is

  • A
    $H_2S$ gas
  • B
    Hot dilute $HCl$ solution
  • C
    $NH_4Cl$ (solid) + $NH_4OH$ (solution)
  • D
    $NH_4Cl$ (solid) + $(NH_4)_2CO_3$ solution

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The group reagent for the precipitation of group $II$ basic radicals in qualitative analysis is:

$A$ salt on treatment with dil. $HCl$ gives a pungent smelling gas and a yellow precipitate. The salt gives a green flame when tested. The salt solution gives a yellow precipitate with potassium chromate. The salt is:

An aqueous solution contains the ions as $Hg_2^{2+}$,$Hg^{2+}$,$Pb^{2+}$,and $Cd^{2+}$. The addition of dilute $HCl$ $(6 \ N)$ precipitates:

When $H_2S$ gas is passed through an $HCl$ solution containing $CuCl_2, HgCl_2, BiCl_3$,and $CoCl_2$,which of the following will not precipitate?

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In qualitative analysis,in order to detect $II$ group basic radicals,$H_2S$ gas is passed in the presence of dilute $HCl$ to:

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