The reagent 'R' in the given sequence of chem | vedclass

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Question

(B) The given reaction sequence involves the conversion of $2,4,6$-tribromoaniline to $2,4,6$-tribromobenzenediazonium chloride using $NaNO_{2} / HCl$

Vedclass · Accepted Answer

$CH_{3}CH_{2}OH$

Vedclass · Answer

(B) The given reaction sequence involves the conversion of $2,4,6$-tribromoaniline to $2,4,6$-tribromobenzenediazonium chloride using $NaNO_{2} / HCl$ at $0-5^{\circ}C$. To replace the diazonium group $(-N_{2}^{+}Cl^{-})$ with a hydrogen atom,a reducing agent is required. Ethanol $(CH_{3}CH_{2}OH)$ acts as a mild reducing agent that reduces the diazonium salt to the corresponding aromatic hydrocarbon (in this case,$1,3,5$-tribromobenzene) while being oxidized to acetaldehyde. Therefore,the reagent '$R$' is $CH_{3}CH_{2}OH$.

The reagent '$R$' in the given sequence of chemical reaction is:

Similar Questions

Arrange the following compounds in decreasing order of basic strength:

The order of basic strength of the following in aqueous solution is
$I$. $C_6H_5NH_2$
$II$. $(CH_3)_3N$
$III$. $NH_3$
$IV$. $CH_3NH_2$
$V$. $(CH_3)_2NH$

Rank the following in decreasing order of their acidic strengths:
$(A)$ Tetrahydrofuran-oxonium ion
$(B)$ Pyrrolidine
$(C)$ Cyclopentanol
$(D)$ $N$-methylpyrrolidinium ion

The correct structures of $A$ and $B$ formed in the following reactions are:

Sulphonation is most favourable at the carbon number $...$

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