The readings of the voltmeter and ammeter in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the given circuit, there are two cells connected in series. The total electromotive force $(EMF)$ is $E_{eq} = 12 \, V - 6 \, V = 6 \, V$ (sinc

Vedclass · Accepted Answer

$7 \, V, 1 \, A$

Vedclass · Answer

(D) In the given circuit, there are two cells connected in series. The total electromotive force $(EMF)$ is $E_{eq} = 12 \, V - 6 \, V = 6 \, V$ (since they are connected in opposition).The total resistance of the circuit is $R_{total} = 4 \, \Omega + 1 \, \Omega + 0.6 \, \Omega + 0.4 \, \Omega = 6 \, \Omega$.The current in the circuit is $I = \frac{E_{eq}}{R_{total}} = \frac{6 \, V}{6 \, \Omega} = 1 \, A$.Thus, the ammeter reading is $1 \, A$.The voltmeter is connected across the $6 \, V$ cell. Since the current flows into the positive terminal of the $6 \, V$ cell, the cell is being charged.The terminal voltage of the $6 \, V$ cell is $V = E + Ir = 6 \, V + (1 \, A)(1 \, \Omega) = 7 \, V$.Therefore, the voltmeter reading is $7 \, V$ and the ammeter reading is $1 \, A$.

The readings of the voltmeter and ammeter in the circuit shown in the diagram are respectively

Similar Questions

When three identical bulbs of $60 \;W, 200 \;V$ rating are connected in series to a $200 \;V$ supply,the power drawn by them will be ....... $Watt$.

In the given electric circuit, the potential difference across $PQ$ is approximately ...... volts.

Total surface area of a cathode is $0.05\,m^2$ and $1\,A$ current passes through it for $1\,hour$. The thickness of nickel deposited on the cathode is (Given that density of nickel $= 9\,g/cm^3$ and its $E.C.E. = 3.04 \times 10^{-4}\,g/C$)

Two cells of same $emf$ $E$ but internal resistances $r_1$ and $r_2$ are connected in series to an external resistor $R$ (as shown in the figure). What should be the value of $R$ so that the potential difference across the terminals of the first cell becomes zero?

For the network shown below, the value of $V_{B} - V_{A}$ is . . . . . . $V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module