The reaction of zinc with an excess of aqueou | vedclass

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Question

(D) Zinc reacts with an excess of aqueous alkali (such as $NaOH$) to evolve hydrogen gas and form the soluble tetrahydroxozincate$(II)$ complex ion.Th

Vedclass · Accepted Answer

$[Zn(OH)_4]^{2-}$

Vedclass · Answer

(D) Zinc reacts with an excess of aqueous alkali (such as $NaOH$) to evolve hydrogen gas and form the soluble tetrahydroxozincate$(II)$ complex ion.The chemical equation is:$Zn(s) + 2OH^{-}(aq) + 2H_2O(l) \rightarrow [Zn(OH)_4]^{2-}(aq) + H_2(g) \uparrow$In this reaction,the zinc metal is oxidized to the $+2$ oxidation state,forming the complex ion $[Zn(OH)_4]^{2-}$,which is the stable species in an aqueous alkaline medium.

The reaction of zinc with an excess of aqueous alkali evolves hydrogen gas and gives:

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