The reaction of methyltrichloroacetate $(Cl_{3}CCO_{2}Me)$ with sodium methoxide $(NaOMe)$ generates

Arrange the following carbocations in the decreasing order of their stability:
$a$. $CH_3-CH^{+}-CH_3$
$b$. $CH_3-CH^{+}-OCH_3$
$c$. $CH_3-CH^{+}-COCH_3$

The correct order of decreasing stability of the following carbocations is:
$I. CH_3-CH^{+}-CH_3$
$II. CH_3-CH^{+}-OCH_3$
$III. CH_3-CH^{+}-CH_2-OCH_3$

Assertion : Carbanions like ammonia have pyramidal shape.
Reason : The carbon atom carrying negative charge has an octet of electrons.

Consider the following carbocations. What is the relative stability order of these carbocations?
$(1)$ $CH_3O-C_6H_4-CH_2^+$
$(2)$ $C_6H_5-CH_2^+$
$(3)$ $CH_3-C_6H_4-CH_2^+$

Which of the following is the most stable carbocation?