The reaction of 4-methyloct-1-ene (P, 2.52 g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Moles of $P$ ($4$-methyloct$-1-$ene) = $\frac{2.52 \ g}{126 \ g \ mol^{-1}} = 0.02 \ mol$.$2$. The reaction with $HBr$ in the presence of per

Vedclass · Accepted Answer

$1791$

Vedclass · Answer

(B) $1$. Moles of $P$ ($4$-methyloct$-1-$ene) = $\frac{2.52 \ g}{126 \ g \ mol^{-1}} = 0.02 \ mol$.$2$. The reaction with $HBr$ in the presence of peroxide follows anti-Markovnikov addition. The combined yield is $50 \%$,so the total moles of bromides formed = $0.02 	imes 0.50 = 0.01 \ mol$.$3$. The bromides are formed in a $9:1$ ratio. The primary alkyl bromide is the major product ($9$ parts out of $10$).$4$. Moles of primary alkyl bromide = $\frac{9}{10} 	imes 0.01 \ mol = 0.009 \ mol$.$5$. The primary alkyl bromide reacts with diethylamine to form a quaternary ammonium salt,which upon treatment with aqueous $K_2CO_3$ yields the non-ionic amine product $S$.$6$. The molar mass of $S$ ($N,N$-diethyl$-4$-methyloctan$-1-$amine) is $199 \ g \ mol^{-1}$.$7$. Mass of $S$ = $	ext{moles} 	imes 	ext{molar mass} = 0.009 \ mol 	imes 199 \ g \ mol^{-1} = 1.791 \ g = 1791 \ mg$.

Similar Questions

In the reaction of hydrogen bromide with an alkene (in the absence of peroxides),the first step of the reaction is the ................. to the alkene.

In the following reaction,$P$ gives two products $Q$ and $R$ each in $40 \,\%$ yield. If the reaction is carried out with $420 \,mg$ of $P$,the reaction yields $108.8 \,mg$ of $Q$. The amount of $R$ produced in the reaction is closest to $....\, mg$.

The major product of the following reaction is:

The action of water in the presence of sulphuric acid on the following alkenes gives:
$(i)$ $CH_3-CH=C(CH_3)_2$
(ii) $CH_3-CH=CH_2$

The reaction,$H_2C=CH_2$ (Ethylene) $+ H_2O$ (water) $\xrightarrow{H_3PO_4, 300 \ ^\circ C/60 \ atm}$ $C_2H_5OH$ (Ethyl alcohol) is called:

Vedclass Test Series

Exam Paper Generator

Online Exam Module