The reaction of $HBr$ with $CH_3-C(CH_3)=CH_2$ in the presence of peroxide will give:
- A$CH_3-C(Br)(CH_3)-CH_3$
- B$CH_3-CH_2-CH_2-CH_2-Br$
- C$CH_3-CH(CH_3)-CH_2Br$
- D$CH_3-CH_2-CH(CH_3)-CH_3$
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