The reaction H_2S + H_2O_2 to S + 2H_2O manif | vedclass

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(C) In the given reaction: $H_2S + H_2O_2 	o S + 2H_2O$. The oxidation state of sulfur in $H_2S$ changes from $-2$ to $0$ in $S$. Since the oxidation

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Oxidising nature of $H_2O_2$

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(C) In the given reaction: $H_2S + H_2O_2 	o S + 2H_2O$. The oxidation state of sulfur in $H_2S$ changes from $-2$ to $0$ in $S$. Since the oxidation state of sulfur increases,$H_2S$ is oxidized. $H_2O_2$ acts as an oxidizing agent because it facilitates the oxidation of $H_2S$ and itself gets reduced to $H_2O$. Therefore,this reaction manifests the oxidising nature of $H_2O_2$.

The reaction $H_2S + H_2O_2 \to S + 2H_2O$ manifests:

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