The reaction of $C_6H_5CH=CHCHO$ with $LiAlH_4$ gives

  • A
    $C_6H_5CH_2CH_2CH_2OH$
  • B
    $C_6H_5CH=CHCH_2OH$
  • C
    $C_6H_5CH_2CH_2CHO$
  • D
    $C_6H_5CH_2CHOHCH_3$

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