(B) In the reaction $\underline{Xe}F_4 + SbF_5 \rightarrow [XeF_3]^+ [SbF_6]^-$,the hybridisation of $Xe$ changes from $sp^3d^2$ in $XeF_4$ to $sp^3d$

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$\underline{Xe}F_4 + SbF_5 \rightarrow [XeF_3]^+ [SbF_6]^-$

(B) In the reaction $\underline{Xe}F_4 + SbF_5 \rightarrow [XeF_3]^+ [SbF_6]^-$,the hybridisation of $Xe$ changes from $sp^3d^2$ in $XeF_4$ to $sp^3d$ in the $[XeF_3]^+$ cation.In $NH_3$,$N$ is $sp^3$ and in $[NH_4]^+$,$N$ is $sp^3$.In $H_2SO_4$,$S$ is $sp^3$ and in $NaHSO_4$,$S$ remains $sp^3$.In $H_3PO_2$,$P$ is $sp^3$ and in $PH_3$ and $H_3PO_3$,$P$ remains $sp^3$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Hybridisation

Medium

The reaction in which the hybridisation of the underlined atom is affected is

JEE MAIN 2020 All JEE MAIN

A
$\underline{N}H_3 \xrightarrow{H^{+}} [NH_4]^+$
B
$\underline{Xe}F_4 + SbF_5 \rightarrow [XeF_3]^+ [SbF_6]^-$
C
$H_2 \underline{S}O_4 + NaCl \xrightarrow{420 \ K} NaHSO_4 + HCl$
D
$H_3 \underline{P}O_2 \xrightarrow{\text{Disproportionation}} PH_3 + H_3PO_3$

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Chemical Bonding and Molecular Structure

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Hybridisation

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Among $SO_2, NF_3, NH_3, XeF_2, ClF_3$ and $SF_4$,the hybridization of the molecule with non$-zero$ dipole moment and highest number of lone$-pairs$ of electrons on the central atom is

MediumJEE MAIN 2025

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Which of the following has a linear structure?

Easy

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Consider the following species: $BrF_5, XeF_5^-, BF_4^-, ICl_4^-, XeF_4, SF_4, NH_4^+, ClF_3, XeF_2, ICl_2^-$. Number of species having $sp^3d$ hybridized central atom is . . . . . . .

MediumJEE MAIN 2026

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Which statement is correct about $CO_2$ if the central atom uses $s + P_x$ orbitals in hybridization?
$(i)$ $\pi$ bond will be formed by $P_y$ and $P_z$
$(ii)$ molecule can be in $XY$ plane
$(iii)$ molecule can be in $XZ$ plane
$(iv)$ molecule can be in infinite plane
$(v)$ molecule can be in $YZ$ plane
Correct code is:

Difficult

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Assertion : Among the carbon allotropes,diamond is an insulator,whereas,graphite is a good conductor of electricity.
Reason : Hybridization of carbon in diamond and graphite are $sp^3$ and $sp^2$,respectively.

DifficultJEE MAIN 2016

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The reaction in which the hybridisation of the underlined atom is affected is

Similar Questions

Among $SO_2, NF_3, NH_3, XeF_2, ClF_3$ and $SF_4$,the hybridization of the molecule with non$-zero$ dipole moment and highest number of lone$-pairs$ of electrons on the central atom is

Which of the following has a linear structure?

Consider the following species: $BrF_5, XeF_5^-, BF_4^-, ICl_4^-, XeF_4, SF_4, NH_4^+, ClF_3, XeF_2, ICl_2^-$. Number of species having $sp^3d$ hybridized central atom is . . . . . . .

Assertion : Among the carbon allotropes,diamond is an insulator,whereas,graphite is a good conductor of electricity.Reason : Hybridization of carbon in diamond and graphite are $sp^3$ and $sp^2$,respectively.

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Assertion : Among the carbon allotropes,diamond is an insulator,whereas,graphite is a good conductor of electricity.
Reason : Hybridization of carbon in diamond and graphite are $sp^3$ and $sp^2$,respectively.