The reaction A_{(g)} + 2B_{(g)} longrightarro | vedclass

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(D) The expression for the initial rate is $r_{0} = k(P_{A})_{0}(P_{B})_{0}^{2} = k(0.60)(0.80)^{2} \dots (1)$After some time,the partial pressure of

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$1/6$

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(D) The expression for the initial rate is $r_{0} = k(P_{A})_{0}(P_{B})_{0}^{2} = k(0.60)(0.80)^{2} \dots (1)$After some time,the partial pressure of $C$ is $0.20 \ atm$. According to the stoichiometry of the reaction $A_{(g)} + 2B_{(g)} \longrightarrow C_{(g)} + D_{(g)}$,the partial pressures of $A$ and $B$ are $P_{A} = 0.60 - 0.20 = 0.40 \ atm$ and $P_{B} = 0.80 - 2(0.20) = 0.40 \ atm$,respectively.The expression for the rate at this instant is $r = k(P_{A})(P_{B})^{2} = k(0.40)(0.40)^{2} \dots (2)$Dividing equation $(2)$ by equation $(1)$:$\frac{r}{r_{0}} = \frac{k(0.40)(0.40)^{2}}{k(0.60)(0.80)^{2}} = \frac{0.40 	imes 0.16}{0.60 	imes 0.64} = \frac{0.064}{0.384} = \frac{1}{6}$

The reaction $A_{(g)} + 2B_{(g)} \longrightarrow C_{(g)} + D_{(g)}$ is an elementary process. In an experiment,the initial partial pressure of $A$ and $B$ are $0.6 \ atm$ and $0.8 \ atm$,respectively. When partial pressure of $C$ is $0.2 \ atm$,the rate of reaction relative to the initial rate is

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