The reaction 2X to B is a zeroth order reacti | vedclass

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(C) For a zero-order reaction,the integrated rate law is given by $C_0 - C_t = Kt$.First,calculate the rate constant $K$ using the half-life formula f

Vedclass · Accepted Answer

$18.0$

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(C) For a zero-order reaction,the integrated rate law is given by $C_0 - C_t = Kt$.First,calculate the rate constant $K$ using the half-life formula for a zero-order reaction: $t_{1/2} = \frac{C_0}{2K}$.Given $t_{1/2} = 6 \ h$ and $C_0 = 0.2 \ M$,we have $6 = \frac{0.2}{2K}$,which gives $K = \frac{0.2}{12} = \frac{1}{60} \ M \ h^{-1}$.Now,for the second condition where initial concentration $C_0 = 0.5 \ M$ and final concentration $C_t = 0.2 \ M$:Using $C_0 - C_t = Kt$,we get $0.5 - 0.2 = Kt$.$0.3 = Kt$.Substituting $K = \frac{1}{60}$,we get $0.3 = \frac{1}{60} 	imes t$.$t = 0.3 	imes 60 = 18 \ h$.

The reaction $2X \to B$ is a zeroth order reaction. If the initial concentration of $X$ is $0.2 \ M$,the half-life is $6 \ h$. When the initial concentration of $X$ is $0.5 \ M$,the time required to reach its final concentration of $0.2 \ M$ will be ........ $hr$.

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